1213330241143 has 4 divisors (see below), whose sum is σ = 1215355834800. Its totient is φ = 1211304647488.

The previous prime is 1213330241117. The next prime is 1213330241191. The reversal of 1213330241143 is 3411420333121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1213330241143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213330245143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1012795930 + ... + 1012797127.

It is an arithmetic number, because the mean of its divisors is an integer number (303838958700).

Almost surely, 2^{1213330241143} is an apocalyptic number.

1213330241143 is a deficient number, since it is larger than the sum of its proper divisors (2025593657).

1213330241143 is an equidigital number, since it uses as much as digits as its factorization.

1213330241143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2025593656.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1213330241143 its reverse (3411420333121), we get a palindrome (4624750574264).

The spelling of 1213330241143 in words is "one trillion, two hundred thirteen billion, three hundred thirty million, two hundred forty-one thousand, one hundred forty-three".