121333433444101 has 4 divisors (see below), whose sum is σ = 121502186481600. Its totient is φ = 121164680406604.

The previous prime is 121333433444087. The next prime is 121333433444129. The reversal of 121333433444101 is 101444334333121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121333433444101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121333433444131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84376517671 + ... + 84376519108.

It is an arithmetic number, because the mean of its divisors is an integer number (30375546620400).

Almost surely, 2^{121333433444101} is an apocalyptic number.

It is an amenable number.

121333433444101 is a deficient number, since it is larger than the sum of its proper divisors (168753037499).

121333433444101 is an equidigital number, since it uses as much as digits as its factorization.

121333433444101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 168753037498.

The product of its (nonzero) digits is 124416, while the sum is 37.

Adding to 121333433444101 its reverse (101444334333121), we get a palindrome (222777767777222).

The spelling of 121333433444101 in words is "one hundred twenty-one trillion, three hundred thirty-three billion, four hundred thirty-three million, four hundred forty-four thousand, one hundred one".