Base | Representation |
---|---|
bin | 1011000010010001110101… |
… | …0100000101111001001011 |
3 | 1120221222101121020121211101 |
4 | 2300210131110011321023 |
5 | 3042244432222324413 |
6 | 41450102400042231 |
7 | 2361431145546325 |
oct | 260443524057113 |
9 | 46858347217741 |
10 | 12133774417483 |
11 | 39589a5371724 |
12 | 143b734603377 |
13 | 6a0296542434 |
14 | 2dd3c647a615 |
15 | 1609622e9edd |
hex | b091d505e4b |
12133774417483 has 4 divisors (see below), whose sum is σ = 12134746765440. Its totient is φ = 12132802069528.
The previous prime is 12133774417421. The next prime is 12133774417489. The reversal of 12133774417483 is 38471447733121.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12133774417483 - 213 = 12133774409291 is a prime.
It is a super-2 number, since 2×121337744174832 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12133774417489) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 486155260 + ... + 486180217.
It is an arithmetic number, because the mean of its divisors is an integer number (3033686691360).
Almost surely, 212133774417483 is an apocalyptic number.
12133774417483 is a deficient number, since it is larger than the sum of its proper divisors (972347957).
12133774417483 is an equidigital number, since it uses as much as digits as its factorization.
12133774417483 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 972347956.
The product of its digits is 9483264, while the sum is 55.
The spelling of 12133774417483 in words is "twelve trillion, one hundred thirty-three billion, seven hundred seventy-four million, four hundred seventeen thousand, four hundred eighty-three".
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