121340002440053 has 4 divisors (see below), whose sum is σ = 121340421910860. Its totient is φ = 121339582969248.

The previous prime is 121340002440049. The next prime is 121340002440071. The reversal of 121340002440053 is 350044200043121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 95987146073809 + 25352856366244 = 9797303^2 + 5035162^2 .

It is a cyclic number.

It is not a de Polignac number, because 121340002440053 - 2² = 121340002440049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121340002439998 and 121340002440025.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121340002940053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209301200 + ... + 209880137.

It is an arithmetic number, because the mean of its divisors is an integer number (30335105477715).

Almost surely, 2^{121340002440053} is an apocalyptic number.

It is an amenable number.

121340002440053 is a deficient number, since it is larger than the sum of its proper divisors (419470807).

121340002440053 is an equidigital number, since it uses as much as digits as its factorization.

121340002440053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 419470806.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 121340002440053 its reverse (350044200043121), we get a palindrome (471384202483174).

The spelling of 121340002440053 in words is "one hundred twenty-one trillion, three hundred forty billion, two million, four hundred forty thousand, fifty-three".