12134004341 has 4 divisors (see below), whose sum is σ = 12139504512. Its totient is φ = 12128504172.

The previous prime is 12134004313. The next prime is 12134004343. The reversal of 12134004341 is 14340043121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12134004341 - 2⁶ = 12134004277 is a prime.

It is a super-2 number, since 2×12134004341² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12134004343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2746775 + ... + 2751188.

It is an arithmetic number, because the mean of its divisors is an integer number (3034876128).

Almost surely, 2^12134004341 is an apocalyptic number.

It is an amenable number.

12134004341 is a deficient number, since it is larger than the sum of its proper divisors (5500171).

12134004341 is an equidigital number, since it uses as much as digits as its factorization.

12134004341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5500170.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12134004341 its reverse (14340043121), we get a palindrome (26474047462).

The spelling of 12134004341 in words is "twelve billion, one hundred thirty-four million, four thousand, three hundred forty-one".