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121340401535 = 547895067463
BaseRepresentation
bin111000100000001110…
…0111001011101111111
3102121012102101001201202
41301000130321131333
53442001120322120
6131424253530115
711523633252413
oct1610034713577
9377172331652
10121340401535
1147507547691
121b6247a393b
13b599ac9882
145c31382d43
1532529c6875
hex1c4073977f

121340401535 has 8 divisors (see below), whose sum is σ = 145638915360. Its totient is φ = 97052032224.

The previous prime is 121340401451. The next prime is 121340401541. The reversal of 121340401535 is 535104043121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 121340401535 - 28 = 121340401279 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121340401498 and 121340401507.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2509787 + ... + 2557676.

It is an arithmetic number, because the mean of its divisors is an integer number (18204864420).

Almost surely, 2121340401535 is an apocalyptic number.

121340401535 is a deficient number, since it is larger than the sum of its proper divisors (24298513825).

121340401535 is an equidigital number, since it uses as much as digits as its factorization.

121340401535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5072257.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 121340401535 its reverse (535104043121), we get a palindrome (656444444656).

The spelling of 121340401535 in words is "one hundred twenty-one billion, three hundred forty million, four hundred one thousand, five hundred thirty-five".

Divisors: 1 5 4789 23945 5067463 25337315 24268080307 121340401535