Base | Representation |
---|---|
bin | 111000100000001110… |
… | …0111001011101111111 |
3 | 102121012102101001201202 |
4 | 1301000130321131333 |
5 | 3442001120322120 |
6 | 131424253530115 |
7 | 11523633252413 |
oct | 1610034713577 |
9 | 377172331652 |
10 | 121340401535 |
11 | 47507547691 |
12 | 1b6247a393b |
13 | b599ac9882 |
14 | 5c31382d43 |
15 | 32529c6875 |
hex | 1c4073977f |
121340401535 has 8 divisors (see below), whose sum is σ = 145638915360. Its totient is φ = 97052032224.
The previous prime is 121340401451. The next prime is 121340401541. The reversal of 121340401535 is 535104043121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 121340401535 - 28 = 121340401279 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121340401498 and 121340401507.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2509787 + ... + 2557676.
It is an arithmetic number, because the mean of its divisors is an integer number (18204864420).
Almost surely, 2121340401535 is an apocalyptic number.
121340401535 is a deficient number, since it is larger than the sum of its proper divisors (24298513825).
121340401535 is an equidigital number, since it uses as much as digits as its factorization.
121340401535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5072257.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 121340401535 its reverse (535104043121), we get a palindrome (656444444656).
The spelling of 121340401535 in words is "one hundred twenty-one billion, three hundred forty million, four hundred one thousand, five hundred thirty-five".
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