1213404313501 has 4 divisors (see below), whose sum is σ = 1214247542400. Its totient is φ = 1212561084604.

The previous prime is 1213404313441. The next prime is 1213404313547. The reversal of 1213404313501 is 1053134043121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1213404313501 - 2³³ = 1204814378909 is a prime.

It is a super-3 number, since 3×1213404313501³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1213404313501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213404313001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 421612291 + ... + 421615168.

It is an arithmetic number, because the mean of its divisors is an integer number (303561885600).

Almost surely, 2^{1213404313501} is an apocalyptic number.

It is an amenable number.

1213404313501 is a deficient number, since it is larger than the sum of its proper divisors (843228899).

1213404313501 is an equidigital number, since it uses as much as digits as its factorization.

1213404313501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 843228898.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 1213404313501 its reverse (1053134043121), we get a palindrome (2266538356622).

The spelling of 1213404313501 in words is "one trillion, two hundred thirteen billion, four hundred four million, three hundred thirteen thousand, five hundred one".