Base | Representation |
---|---|
bin | 111000100000001111… |
… | …1010001010000000011 |
3 | 102121012110112122112200 |
4 | 1301000133101100003 |
5 | 3442001300220420 |
6 | 131424315124243 |
7 | 11523641452065 |
oct | 1610037212003 |
9 | 377173478480 |
10 | 121341023235 |
11 | 47507931793 |
12 | 1b624a43683 |
13 | b599c86843 |
14 | 5c314a5735 |
15 | 3252a9ab90 |
hex | 1c407d1403 |
121341023235 has 72 divisors (see below), whose sum is σ = 218475020400. Its totient is φ = 62297835264.
The previous prime is 121341023231. The next prime is 121341023263. The reversal of 121341023235 is 532320143121.
121341023235 is a `hidden beast` number, since 1 + 2 + 13 + 410 + 2 + 3 + 235 = 666.
It is not a de Polignac number, because 121341023235 - 22 = 121341023231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121341023199 and 121341023208.
It is not an unprimeable number, because it can be changed into a prime (121341023231) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 13203312 + ... + 13212498.
Almost surely, 2121341023235 is an apocalyptic number.
121341023235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
121341023235 is a deficient number, since it is larger than the sum of its proper divisors (97133997165).
121341023235 is a wasteful number, since it uses less digits than its factorization.
121341023235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9605 (or 9573 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 121341023235 its reverse (532320143121), we get a palindrome (653661166356).
The spelling of 121341023235 in words is "one hundred twenty-one billion, three hundred forty-one million, twenty-three thousand, two hundred thirty-five".
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