Base | Representation |
---|---|
bin | 111000100000010000… |
… | …0111001011110101001 |
3 | 102121012111100100011110 |
4 | 1301000200321132221 |
5 | 3442001402401103 |
6 | 131424332220533 |
7 | 11523645210540 |
oct | 1610040713651 |
9 | 377174310143 |
10 | 121341450153 |
11 | 475080a3510 |
12 | 1b62500a749 |
13 | b59a0a5c61 |
14 | 5c31577157 |
15 | 3252b32403 |
hex | 1c408397a9 |
121341450153 has 16 divisors (see below), whose sum is σ = 201710462976. Its totient is φ = 63034519440.
The previous prime is 121341450151. The next prime is 121341450157. The reversal of 121341450153 is 351054143121.
It is not a de Polignac number, because 121341450153 - 21 = 121341450151 is a prime.
It is a super-6 number, since 6×1213414501536 (a number of 68 digits) contains 666666 as substring.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 121341450153.
It is not an unprimeable number, because it can be changed into a prime (121341450151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 262643601 + ... + 262644062.
It is an arithmetic number, because the mean of its divisors is an integer number (12606903936).
Almost surely, 2121341450153 is an apocalyptic number.
It is an amenable number.
121341450153 is a deficient number, since it is larger than the sum of its proper divisors (80369012823).
121341450153 is a wasteful number, since it uses less digits than its factorization.
121341450153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 525287684.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 121341450153 its reverse (351054143121), we get a palindrome (472395593274).
The spelling of 121341450153 in words is "one hundred twenty-one billion, three hundred forty-one million, four hundred fifty thousand, one hundred fifty-three".
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