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12134153143 = 71733450449
BaseRepresentation
bin10110100110100000…
…00111101110110111
31011022122112211212101
423103100013232313
5144322320400033
65324021002531
7606460412530
oct132320075667
934278484771
1012134153143
11516745a942
122427853447
1311b4ba5798
1483177d687
154b041e97d
hex2d3407bb7

12134153143 has 4 divisors (see below), whose sum is σ = 13867603600. Its totient is φ = 10400702688.

The previous prime is 12134153099. The next prime is 12134153147. The reversal of 12134153143 is 34135143121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34135143121 = 169720114993.

It is a cyclic number.

It is not a de Polignac number, because 12134153143 - 213 = 12134144951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12134153147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 866725218 + ... + 866725231.

It is an arithmetic number, because the mean of its divisors is an integer number (3466900900).

Almost surely, 212134153143 is an apocalyptic number.

12134153143 is a deficient number, since it is larger than the sum of its proper divisors (1733450457).

12134153143 is an equidigital number, since it uses as much as digits as its factorization.

12134153143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1733450456.

The product of its digits is 4320, while the sum is 28.

Adding to 12134153143 its reverse (34135143121), we get a palindrome (46269296264).

The spelling of 12134153143 in words is "twelve billion, one hundred thirty-four million, one hundred fifty-three thousand, one hundred forty-three".

Divisors: 1 7 1733450449 12134153143