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1213423125441 = 3404474375147
BaseRepresentation
bin10001101010000101101…
…001111000001111000001
311022000001112200112102120
4101222011221320033001
5124340042310003231
62325234444434453
7153444520246362
oct21520551701701
94260045615376
101213423125441
114286787a199a
12177204b48a29
138a56b536b97
1442a31157b69
152186d36cd96
hex11a85a783c1

1213423125441 has 4 divisors (see below), whose sum is σ = 1617897500592. Its totient is φ = 808948750292.

The previous prime is 1213423125433. The next prime is 1213423125493. The reversal of 1213423125441 is 1445213243121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1213423125441 - 23 = 1213423125433 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1213423125641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202237187571 + ... + 202237187576.

It is an arithmetic number, because the mean of its divisors is an integer number (404474375148).

Almost surely, 21213423125441 is an apocalyptic number.

It is an amenable number.

1213423125441 is a deficient number, since it is larger than the sum of its proper divisors (404474375151).

1213423125441 is an equidigital number, since it uses as much as digits as its factorization.

1213423125441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 404474375150.

The product of its digits is 23040, while the sum is 33.

Adding to 1213423125441 its reverse (1445213243121), we get a palindrome (2658636368562).

The spelling of 1213423125441 in words is "one trillion, two hundred thirteen billion, four hundred twenty-three million, one hundred twenty-five thousand, four hundred forty-one".

Divisors: 1 3 404474375147 1213423125441