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1213423125433 is a prime number
BaseRepresentation
bin10001101010000101101…
…001111000001110111001
311022000001112200112102021
4101222011221320032321
5124340042310003213
62325234444434441
7153444520246351
oct21520551701671
94260045615367
101213423125433
114286787a1992
12177204b48a21
138a56b536b8c
1442a31157b61
152186d36cd8d
hex11a85a783b9

1213423125433 has 2 divisors, whose sum is σ = 1213423125434. Its totient is φ = 1213423125432.

The previous prime is 1213423125367. The next prime is 1213423125493. The reversal of 1213423125433 is 3345213243121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1086998078464 + 126425046969 = 1042592^2 + 355563^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1213423125433 is a prime.

It is not a weakly prime, because it can be changed into another prime (1213423125493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606711562716 + 606711562717.

It is an arithmetic number, because the mean of its divisors is an integer number (606711562717).

Almost surely, 21213423125433 is an apocalyptic number.

It is an amenable number.

1213423125433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213423125433 is an equidigital number, since it uses as much as digits as its factorization.

1213423125433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 51840, while the sum is 34.

Adding to 1213423125433 its reverse (3345213243121), we get a palindrome (4558636368554).

The spelling of 1213423125433 in words is "one trillion, two hundred thirteen billion, four hundred twenty-three million, one hundred twenty-five thousand, four hundred thirty-three".