Base | Representation |
---|---|
bin | 10001101010000101110… |
… | …001111111111011100011 |
3 | 11022000001200200200102100 |
4 | 101222011301333323203 |
5 | 124340043331112430 |
6 | 2325235002221443 |
7 | 153444544323414 |
oct | 21520561777343 |
9 | 4260050620370 |
10 | 1213425254115 |
11 | 428679a16228 |
12 | 1772057b4883 |
13 | 8a56bb00a59 |
14 | 42a3154d80b |
15 | 2186d63d960 |
hex | 11a85c7fee3 |
1213425254115 has 48 divisors (see below), whose sum is σ = 2133582628320. Its totient is φ = 637845788160.
The previous prime is 1213425254087. The next prime is 1213425254131. The reversal of 1213425254115 is 5114525243121.
1213425254115 is a `hidden beast` number, since 1 + 2 + 13 + 4 + 2 + 525 + 4 + 115 = 666.
It is not a de Polignac number, because 1213425254115 - 237 = 1075986300643 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1213425254115.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4565020 + ... + 4823510.
It is an arithmetic number, because the mean of its divisors is an integer number (44449638090).
Almost surely, 21213425254115 is an apocalyptic number.
1213425254115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1213425254115 is a deficient number, since it is larger than the sum of its proper divisors (920157374205).
1213425254115 is a wasteful number, since it uses less digits than its factorization.
1213425254115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260004 (or 260001 counting only the distinct ones).
The product of its digits is 48000, while the sum is 36.
The spelling of 1213425254115 in words is "one trillion, two hundred thirteen billion, four hundred twenty-five million, two hundred fifty-four thousand, one hundred fifteen".
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