Base | Representation |
---|---|
bin | 10001101010000111010… |
… | …001001011001111100111 |
3 | 11022000010102122021102011 |
4 | 101222013101023033213 |
5 | 124340121223013020 |
6 | 2325241253055051 |
7 | 153445266360121 |
oct | 21520721131747 |
9 | 4260112567364 |
10 | 1213450204135 |
11 | 428692007584 |
12 | 177212027487 |
13 | 8a574028290 |
14 | 42a349a6211 |
15 | 2187091b35a |
hex | 11a8744b3e7 |
1213450204135 has 16 divisors (see below), whose sum is σ = 1568191748256. Its totient is φ = 896063038848.
The previous prime is 1213450204069. The next prime is 1213450204207. The reversal of 1213450204135 is 5314020543121.
It is a cyclic number.
It is not a de Polignac number, because 1213450204135 - 211 = 1213450202087 is a prime.
It is a super-2 number, since 2×12134502041352 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1213450204097 and 1213450204106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2520897 + ... + 2963413.
It is an arithmetic number, because the mean of its divisors is an integer number (98011984266).
Almost surely, 21213450204135 is an apocalyptic number.
1213450204135 is a deficient number, since it is larger than the sum of its proper divisors (354741544121).
1213450204135 is a wasteful number, since it uses less digits than its factorization.
1213450204135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 484722.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1213450204135 its reverse (5314020543121), we get a palindrome (6527470747256).
The spelling of 1213450204135 in words is "one trillion, two hundred thirteen billion, four hundred fifty million, two hundred four thousand, one hundred thirty-five".
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