Base | Representation |
---|---|
bin | 10110100110100111… |
… | …10010110011000011 |
3 | 1011022201100202121200 |
4 | 23103103302303003 |
5 | 144323042202341 |
6 | 5324053352243 |
7 | 606501532566 |
oct | 132323626303 |
9 | 34281322550 |
10 | 12135115971 |
11 | 5167a58270 |
12 | 2428038683 |
13 | 11b5151ac4 |
14 | 8319504dd |
15 | 4b055edb6 |
hex | 2d34f2cc3 |
12135115971 has 24 divisors (see below), whose sum is σ = 19146859056. Its totient is φ = 7345055040.
The previous prime is 12135115969. The next prime is 12135115973. The reversal of 12135115971 is 17951153121.
12135115971 is a `hidden beast` number, since 1 + 2 + 13 + 51 + 1 + 597 + 1 = 666.
It is an interprime number because it is at equal distance from previous prime (12135115969) and next prime (12135115973).
It is not a de Polignac number, because 12135115971 - 21 = 12135115969 is a prime.
It is a super-2 number, since 2×121351159712 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12135115973) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2760 + ... + 155813.
It is an arithmetic number, because the mean of its divisors is an integer number (797785794).
Almost surely, 212135115971 is an apocalyptic number.
12135115971 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
12135115971 is a deficient number, since it is larger than the sum of its proper divisors (7011743085).
12135115971 is a wasteful number, since it uses less digits than its factorization.
12135115971 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159363 (or 159360 counting only the distinct ones).
The product of its digits is 9450, while the sum is 36.
The spelling of 12135115971 in words is "twelve billion, one hundred thirty-five million, one hundred fifteen thousand, nine hundred seventy-one".
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