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12135443153 = 29418463557
BaseRepresentation
bin10110100110101010…
…00010101011010001
31011022201222101102112
423103111002223101
5144323133140103
65324104355105
7606504364511
oct132325025321
934281871375
1012135443153
115168161069
122428175a95
1311b52379c2
148319d7841
154b05c6cd8
hex2d3542ad1

12135443153 has 4 divisors (see below), whose sum is σ = 12553906740. Its totient is φ = 11716979568.

The previous prime is 12135443147. The next prime is 12135443161. The reversal of 12135443153 is 35134453121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6085248064 + 6050195089 = 78008^2 + 77783^2 .

It is a cyclic number.

It is not a de Polignac number, because 12135443153 - 28 = 12135442897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12135443953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209231750 + ... + 209231807.

It is an arithmetic number, because the mean of its divisors is an integer number (3138476685).

Almost surely, 212135443153 is an apocalyptic number.

It is an amenable number.

12135443153 is a deficient number, since it is larger than the sum of its proper divisors (418463587).

12135443153 is an equidigital number, since it uses as much as digits as its factorization.

12135443153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 418463586.

The product of its digits is 21600, while the sum is 32.

Adding to 12135443153 its reverse (35134453121), we get a palindrome (47269896274).

The spelling of 12135443153 in words is "twelve billion, one hundred thirty-five million, four hundred forty-three thousand, one hundred fifty-three".

Divisors: 1 29 418463557 12135443153