Base | Representation |
---|---|
bin | 10110100110110001… |
… | …00001011011001111 |
3 | 1011022210200201222110 |
4 | 23103120201123033 |
5 | 144323401334120 |
6 | 5324140115103 |
7 | 606515214513 |
oct | 132330413317 |
9 | 34283621873 |
10 | 12136355535 |
11 | 51687245a7 |
12 | 2428535a93 |
13 | 11b5497085 |
14 | 831b94143 |
15 | 4b07072e0 |
hex | 2d36216cf |
12136355535 has 16 divisors (see below), whose sum is σ = 19691665920. Its totient is φ = 6381557280.
The previous prime is 12136355521. The next prime is 12136355591. The reversal of 12136355535 is 53555363121.
It is not a de Polignac number, because 12136355535 - 210 = 12136354511 is a prime.
It is a super-2 number, since 2×121363555352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12136355493 and 12136355502.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5696755 + ... + 5698884.
It is an arithmetic number, because the mean of its divisors is an integer number (1230729120).
Almost surely, 212136355535 is an apocalyptic number.
12136355535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12136355535 is a deficient number, since it is larger than the sum of its proper divisors (7555310385).
12136355535 is a wasteful number, since it uses less digits than its factorization.
12136355535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11395718.
The product of its digits is 202500, while the sum is 39.
The spelling of 12136355535 in words is "twelve billion, one hundred thirty-six million, three hundred fifty-five thousand, five hundred thirty-five".
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