Base | Representation |
---|---|
bin | 10110100110110011… |
… | …01000001000001101 |
3 | 1011022211020110020022 |
4 | 23103121220020031 |
5 | 144323440121013 |
6 | 5324150231525 |
7 | 606520532024 |
oct | 132331501015 |
9 | 34284213208 |
10 | 12136645133 |
11 | 5168902138 |
12 | 24286555a5 |
13 | 11b5568b32 |
14 | 831c2b8bb |
15 | 4b0763008 |
hex | 2d366820d |
12136645133 has 4 divisors (see below), whose sum is σ = 12143971260. Its totient is φ = 12129319008.
The previous prime is 12136645099. The next prime is 12136645153. The reversal of 12136645133 is 33154663121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4282786249 + 7853858884 = 65443^2 + 88622^2 .
It is a cyclic number.
It is not a de Polignac number, because 12136645133 - 210 = 12136644109 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12136645093 and 12136645102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12136645153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3660578 + ... + 3663891.
It is an arithmetic number, because the mean of its divisors is an integer number (3035992815).
Almost surely, 212136645133 is an apocalyptic number.
It is an amenable number.
12136645133 is a deficient number, since it is larger than the sum of its proper divisors (7326127).
12136645133 is an equidigital number, since it uses as much as digits as its factorization.
12136645133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7326126.
The product of its digits is 38880, while the sum is 35.
The spelling of 12136645133 in words is "twelve billion, one hundred thirty-six million, six hundred forty-five thousand, one hundred thirty-three".
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