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12138509926400 = 215521113103619
BaseRepresentation
bin1011000010100011011110…
…0100101000000000000000
31120222102121121221101211112
42300220313210220000000
53042334132020121100
641452204322302452
72361656406655634
oct260506744500000
946872547841745
1012138509926400
11395aa05448660
1214406364b7a28
136a086c656810
142dd71536cdc4
15160b3ce08b35
hexb0a37928000

12138509926400 has 384 divisors, whose sum is σ = 35366156733600. Its totient is φ = 4074425548800.

The previous prime is 12138509926391. The next prime is 12138509926421. The reversal of 12138509926400 is 462990583121.

It is a super-2 number, since 2×121385099264002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (50).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 117093791 + ... + 117197409.

Almost surely, 212138509926400 is an apocalyptic number.

12138509926400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12138509926400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17683078366800).

12138509926400 is an abundant number, since it is smaller than the sum of its proper divisors (23227646807200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12138509926400 is a wasteful number, since it uses less digits than its factorization.

12138509926400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103683 (or 103650 counting only the distinct ones).

The product of its (nonzero) digits is 933120, while the sum is 50.

The spelling of 12138509926400 in words is "twelve trillion, one hundred thirty-eight billion, five hundred nine million, nine hundred twenty-six thousand, four hundred".