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12140011131 = 338310565719
BaseRepresentation
bin10110100111001100…
…11101111001111011
31011100001120110111220
423103212131321323
5144330320324011
65324350323123
7606561251313
oct132346357173
934301513456
1012140011131
11516a7a1056
1224297b94a3
1311b6176c51
14832466443
154b0bca506
hex2d399de7b

12140011131 has 8 divisors (see below), whose sum is σ = 16228945920. Its totient is φ = 8072208552.

The previous prime is 12140011111. The next prime is 12140011139. The reversal of 12140011131 is 13111004121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12140011131 - 25 = 12140011099 is a prime.

It is a super-2 number, since 2×121400111312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12140011131.

It is not an unprimeable number, because it can be changed into a prime (12140011139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5281711 + ... + 5284008.

It is an arithmetic number, because the mean of its divisors is an integer number (2028618240).

Almost surely, 212140011131 is an apocalyptic number.

12140011131 is a deficient number, since it is larger than the sum of its proper divisors (4088934789).

12140011131 is a wasteful number, since it uses less digits than its factorization.

12140011131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10566105.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 12140011131 its reverse (13111004121), we get a palindrome (25251015252).

The spelling of 12140011131 in words is "twelve billion, one hundred forty million, eleven thousand, one hundred thirty-one".

Divisors: 1 3 383 1149 10565719 31697157 4046670377 12140011131