Base | Representation |
---|---|
bin | 10110100111001101… |
… | …00001011001100011 |
3 | 1011100001121012010222 |
4 | 23103212201121203 |
5 | 144330321303233 |
6 | 5324350513255 |
7 | 606561341120 |
oct | 132346413143 |
9 | 34301535128 |
10 | 12140025443 |
11 | 516a800887 |
12 | 242980582b |
13 | 11b6180610 |
14 | 83246b747 |
15 | 4b0bce898 |
hex | 2d39a1663 |
12140025443 has 32 divisors (see below), whose sum is σ = 15478041600. Its totient is φ = 9261334656.
The previous prime is 12140025323. The next prime is 12140025449. The reversal of 12140025443 is 34452004121.
12140025443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12140025443 - 214 = 12140009059 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12140025449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2211380 + ... + 2216862.
It is an arithmetic number, because the mean of its divisors is an integer number (483688800).
Almost surely, 212140025443 is an apocalyptic number.
12140025443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12140025443 is a deficient number, since it is larger than the sum of its proper divisors (3338016157).
12140025443 is a wasteful number, since it uses less digits than its factorization.
12140025443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6371.
The product of its (nonzero) digits is 3840, while the sum is 26.
Adding to 12140025443 its reverse (34452004121), we get a palindrome (46592029564).
The spelling of 12140025443 in words is "twelve billion, one hundred forty million, twenty-five thousand, four hundred forty-three".
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