Base | Representation |
---|---|
bin | 11011100110100111101100… |
… | …100111010001100100100000 |
3 | 120220211211202210001112012002 |
4 | 123212213230213101210200 |
5 | 111403014144401340000 |
6 | 1110110541203423132 |
7 | 34366643261435606 |
oct | 3346475447214440 |
9 | 526754683045162 |
10 | 121401220340000 |
11 | 35755a71a5aa57 |
12 | 11748453084aa8 |
13 | 5298116aca103 |
14 | 21d9bc9781876 |
15 | e07dce9bc8d5 |
hex | 6e69ec9d1920 |
121401220340000 has 240 divisors, whose sum is σ = 304186181213376. Its totient is φ = 47666102400000.
The previous prime is 121401220339967. The next prime is 121401220340069. The reversal of 121401220340000 is 43022104121.
It is a super-3 number, since 3×1214012203400003 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 594037835 + ... + 594242165.
Almost surely, 2121401220340000 is an apocalyptic number.
121401220340000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 121401220340000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (152093090606688).
121401220340000 is an abundant number, since it is smaller than the sum of its proper divisors (182784960873376).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121401220340000 is an equidigital number, since it uses as much as digits as its factorization.
121401220340000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 204909 (or 204886 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 121401220340000 its reverse (43022104121), we get a palindrome (121444242444121).
The spelling of 121401220340000 in words is "one hundred twenty-one trillion, four hundred one billion, two hundred twenty million, three hundred forty thousand".
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