12140301114533 has 4 divisors (see below), whose sum is σ = 12140308247340. Its totient is φ = 12140293981728.

The previous prime is 12140301114503. The next prime is 12140301114619. The reversal of 12140301114533 is 33541110304121.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 2223552180964 + 9916748933569 = 1491158^2 + 3149087^2 .

It is a cyclic number.

It is not a de Polignac number, because 12140301114533 - 2²² = 12140296920229 is a prime.

It is a super-2 number, since 2×12140301114533² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12140301114496 and 12140301114505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12140301114503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641891 + ... + 4969167.

It is an arithmetic number, because the mean of its divisors is an integer number (3035077061835).

Almost surely, 2^{12140301114533} is an apocalyptic number.

It is an amenable number.

12140301114533 is a deficient number, since it is larger than the sum of its proper divisors (7132807).

12140301114533 is an equidigital number, since it uses as much as digits as its factorization.

12140301114533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7132806.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 12140301114533 its reverse (33541110304121), we get a palindrome (45681411418654).

The spelling of 12140301114533 in words is "twelve trillion, one hundred forty billion, three hundred one million, one hundred fourteen thousand, five hundred thirty-three".