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1214121101113 = 9941122132693
BaseRepresentation
bin10001101010101111010…
…000011100011100111001
311022001212012001101001101
4101222233100130130321
5124343010000213423
62325432020451401
7153501024040024
oct21525720343471
94261765041041
101214121101113
114289a6789398
1217737a849b61
138a650017a3b
1442a99b261bb
15218ae7907ad
hex11aaf41c739

1214121101113 has 4 divisors (see below), whose sum is σ = 1214243243748. Its totient is φ = 1213998958480.

The previous prime is 1214121101093. The next prime is 1214121101227. The reversal of 1214121101113 is 3111011214121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13194427689 + 1200926673424 = 114867^2 + 1095868^2 .

It is a cyclic number.

It is not a de Polignac number, because 1214121101113 - 237 = 1076682147641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1214121102113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61056406 + ... + 61076287.

It is an arithmetic number, because the mean of its divisors is an integer number (303560810937).

Almost surely, 21214121101113 is an apocalyptic number.

It is an amenable number.

1214121101113 is a deficient number, since it is larger than the sum of its proper divisors (122142635).

1214121101113 is an equidigital number, since it uses as much as digits as its factorization.

1214121101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122142634.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 1214121101113 its reverse (3111011214121), we get a palindrome (4325132315234).

The spelling of 1214121101113 in words is "one trillion, two hundred fourteen billion, one hundred twenty-one million, one hundred one thousand, one hundred thirteen".

Divisors: 1 9941 122132693 1214121101113