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1214140110113 = 7178397279073
BaseRepresentation
bin10001101010110000011…
…000111101010100100001
311022001220111211010111102
4101222300120331110201
5124343024332010423
62325433540124145
7153501344440610
oct21526030752441
94261814733442
101214140110113
11428a06492107
12177385096655
138a653c42078
1442a9c473877
15218b1297c28
hex11ab063d521

1214140110113 has 8 divisors (see below), whose sum is σ = 1388366944128. Its totient is φ = 1040107837824.

The previous prime is 1214140110067. The next prime is 1214140110163. The reversal of 1214140110113 is 3110110414121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1214140110113 - 28 = 1214140109857 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1214140110163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48627056 + ... + 48652017.

It is an arithmetic number, because the mean of its divisors is an integer number (173545868016).

Almost surely, 21214140110113 is an apocalyptic number.

It is an amenable number.

1214140110113 is a deficient number, since it is larger than the sum of its proper divisors (174226834015).

1214140110113 is an equidigital number, since it uses as much as digits as its factorization.

1214140110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97280863.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 1214140110113 its reverse (3110110414121), we get a palindrome (4324250524234).

The spelling of 1214140110113 in words is "one trillion, two hundred fourteen billion, one hundred forty million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 7 1783 12481 97279073 680953511 173448587159 1214140110113