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1214154052141 = 5279229996979
BaseRepresentation
bin10001101010110001001…
…110001001001000101101
311022001221111001110100211
4101222301032021020231
5124343041414132031
62325435155022421
7153501604106122
oct21526116111055
94261844043324
101214154052141
11428a13344a48
1217738989aa11
138a656ab3ca4
1442aa0262749
15218b25edbb1
hex11ab138922d

1214154052141 has 4 divisors (see below), whose sum is σ = 1214384054400. Its totient is φ = 1213924049884.

The previous prime is 1214154052123. The next prime is 1214154052151. The reversal of 1214154052141 is 1412504514121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1214154052141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214154052151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114993211 + ... + 115003768.

It is an arithmetic number, because the mean of its divisors is an integer number (303596013600).

Almost surely, 21214154052141 is an apocalyptic number.

It is an amenable number.

1214154052141 is a deficient number, since it is larger than the sum of its proper divisors (230002259).

1214154052141 is an equidigital number, since it uses as much as digits as its factorization.

1214154052141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 230002258.

The product of its (nonzero) digits is 6400, while the sum is 31.

Adding to 1214154052141 its reverse (1412504514121), we get a palindrome (2626658566262).

The spelling of 1214154052141 in words is "one trillion, two hundred fourteen billion, one hundred fifty-four million, fifty-two thousand, one hundred forty-one".

Divisors: 1 5279 229996979 1214154052141