Base | Representation |
---|---|
bin | 10001101010110100110… |
… | …000001010000001001101 |
3 | 11022002002121112120120010 |
4 | 101222310300022001031 |
5 | 124343202101102201 |
6 | 2325445112543433 |
7 | 153503223522231 |
oct | 21526460120115 |
9 | 4262077476503 |
10 | 1214213300301 |
11 | 428a43831a71 |
12 | 1773a56b1b79 |
13 | 8a666159981 |
14 | 42aa80865c1 |
15 | 218b7903bd6 |
hex | 11ab4c0a04d |
1214213300301 has 4 divisors (see below), whose sum is σ = 1618951067072. Its totient is φ = 809475533532.
The previous prime is 1214213300219. The next prime is 1214213300303. The reversal of 1214213300301 is 1030033124121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1214213300301 - 211 = 1214213298253 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1214213300303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202368883381 + ... + 202368883386.
It is an arithmetic number, because the mean of its divisors is an integer number (404737766768).
Almost surely, 21214213300301 is an apocalyptic number.
It is an amenable number.
1214213300301 is a deficient number, since it is larger than the sum of its proper divisors (404737766771).
1214213300301 is an equidigital number, since it uses as much as digits as its factorization.
1214213300301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 404737766770.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1214213300301 its reverse (1030033124121), we get a palindrome (2244246424422).
The spelling of 1214213300301 in words is "one trillion, two hundred fourteen billion, two hundred thirteen million, three hundred thousand, three hundred one".
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