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1214214243403 = 71742124236297
BaseRepresentation
bin10001101010110100110…
…011110000010001001011
311022002002200022111020211
4101222310303300101023
5124343202321242103
62325445145101551
7153503234530630
oct21526463602113
94262080274224
101214214243403
11428a44316597
121773a5a878b7
138a6663ca015
1442aa8250187
15218b7a3d36d
hex11ab4cf044b

1214214243403 has 16 divisors (see below), whose sum is σ = 1472791356864. Its totient is φ = 977207454720.

The previous prime is 1214214243377. The next prime is 1214214243439. The reversal of 1214214243403 is 3043424124121.

It is a happy number.

It is not a de Polignac number, because 1214214243403 - 213 = 1214214235211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1214214243443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12068050 + ... + 12168247.

It is an arithmetic number, because the mean of its divisors is an integer number (92049459804).

Almost surely, 21214214243403 is an apocalyptic number.

1214214243403 is a deficient number, since it is larger than the sum of its proper divisors (258577113461).

1214214243403 is a wasteful number, since it uses less digits than its factorization.

1214214243403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24236742.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 1214214243403 its reverse (3043424124121), we get a palindrome (4257638367524).

The spelling of 1214214243403 in words is "one trillion, two hundred fourteen billion, two hundred fourteen million, two hundred forty-three thousand, four hundred three".

Divisors: 1 7 17 119 421 2947 7157 50099 24236297 169654079 412017049 2884119343 10203481037 71424367259 173459177629 1214214243403