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1214230003303 = 1427850896989
BaseRepresentation
bin10001101010110101101…
…111110111111001100111
311022002010202222011202211
4101222311233313321213
5124343220340101203
62325450510544251
7153503515510102
oct21526557677147
94262122864684
101214230003303
11428a522001a9
121773ab208087
138a6697574c5
1442aaa393739
15218b9102c6d
hex11ab5bf7e67

1214230003303 has 4 divisors (see below), whose sum is σ = 1215080901720. Its totient is φ = 1213379104888.

The previous prime is 1214230003271. The next prime is 1214230003319. The reversal of 1214230003303 is 3033000324121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1214230003303 - 25 = 1214230003271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214230003603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425447068 + ... + 425449921.

It is an arithmetic number, because the mean of its divisors is an integer number (303770225430).

Almost surely, 21214230003303 is an apocalyptic number.

1214230003303 is a deficient number, since it is larger than the sum of its proper divisors (850898417).

1214230003303 is an equidigital number, since it uses as much as digits as its factorization.

1214230003303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 850898416.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 1214230003303 its reverse (3033000324121), we get a palindrome (4247230327424).

The spelling of 1214230003303 in words is "one trillion, two hundred fourteen billion, two hundred thirty million, three thousand, three hundred three".

Divisors: 1 1427 850896989 1214230003303