Search a number
-
+
121430403313 = 218635554151
BaseRepresentation
bin111000100010111010…
…0001110100011110001
3102121102200201121221221
41301011310032203301
53442142140401223
6131441230545041
711526105253312
oct1610564164361
9377380647857
10121430403313
114755332a31a
121b64a968181
13b5b264c56b
145c3d2d0609
15325a853b5d
hex1c45d0e8f1

121430403313 has 4 divisors (see below), whose sum is σ = 121435979328. Its totient is φ = 121424827300.

The previous prime is 121430403301. The next prime is 121430403337. The reversal of 121430403313 is 313304034121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121430403313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121430403343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2755213 + ... + 2798938.

It is an arithmetic number, because the mean of its divisors is an integer number (30358994832).

Almost surely, 2121430403313 is an apocalyptic number.

It is an amenable number.

121430403313 is a deficient number, since it is larger than the sum of its proper divisors (5576015).

121430403313 is an equidigital number, since it uses as much as digits as its factorization.

121430403313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5576014.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 121430403313 its reverse (313304034121), we get a palindrome (434734437434).

The spelling of 121430403313 in words is "one hundred twenty-one billion, four hundred thirty million, four hundred three thousand, three hundred thirteen".

Divisors: 1 21863 5554151 121430403313