Base | Representation |
---|---|
bin | 11011100111000011011101… |
… | …100010100000110000010011 |
3 | 120220221200201102100010220120 |
4 | 123213003131202200300103 |
5 | 111404011223221014212 |
6 | 1110132351315241323 |
7 | 34402050115213110 |
oct | 3347033542406023 |
9 | 526850642303816 |
10 | 121431032204307 |
11 | 3576767aa84941 |
12 | 11752192ba9243 |
13 | 529ab882001c7 |
14 | 21db416c15907 |
15 | e08a76d3288c |
hex | 6e70dd8a0c13 |
121431032204307 has 128 divisors (see below), whose sum is σ = 199773739376640. Its totient is φ = 64030713200640.
The previous prime is 121431032204303. The next prime is 121431032204329. The reversal of 121431032204307 is 703402230134121.
It is not a de Polignac number, because 121431032204307 - 22 = 121431032204303 is a prime.
It is not an unprimeable number, because it can be changed into a prime (121431032204303) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 25335076303 + ... + 25335081095.
It is an arithmetic number, because the mean of its divisors is an integer number (1560732338880).
Almost surely, 2121431032204307 is an apocalyptic number.
121431032204307 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
121431032204307 is a deficient number, since it is larger than the sum of its proper divisors (78342707172333).
121431032204307 is a wasteful number, since it uses less digits than its factorization.
121431032204307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8373.
The product of its (nonzero) digits is 24192, while the sum is 33.
Adding to 121431032204307 its reverse (703402230134121), we get a palindrome (824833262338428).
The spelling of 121431032204307 in words is "one hundred twenty-one trillion, four hundred thirty-one billion, thirty-two million, two hundred four thousand, three hundred seven".
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