Base | Representation |
---|---|
bin | 100100001100000… |
… | …1111101101000001 |
3 | 10010121221121110211 |
4 | 1020120033231001 |
5 | 4441331042304 |
6 | 320254554121 |
7 | 42043336633 |
oct | 11030175501 |
9 | 3117847424 |
10 | 1214315329 |
11 | 5734a4097 |
12 | 29a808941 |
13 | 1647672a6 |
14 | b73b8a53 |
15 | 71917204 |
hex | 4860fb41 |
1214315329 has 4 divisors (see below), whose sum is σ = 1214571520. Its totient is φ = 1214059140.
The previous prime is 1214315317. The next prime is 1214315341. The reversal of 1214315329 is 9235134121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (1214315317) and next prime (1214315341).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1214315329 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1214315329.
It is not an unprimeable number, because it can be changed into a prime (1214315309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120849 + ... + 130510.
It is an arithmetic number, because the mean of its divisors is an integer number (303642880).
Almost surely, 21214315329 is an apocalyptic number.
It is an amenable number.
1214315329 is a deficient number, since it is larger than the sum of its proper divisors (256191).
1214315329 is an equidigital number, since it uses as much as digits as its factorization.
1214315329 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 256190.
The product of its digits is 6480, while the sum is 31.
The square root of 1214315329 is about 34847.0275489890. The cubic root of 1214315329 is about 1066.8675173320.
It can be divided in two parts, 12143 and 15329, that added together give a palindrome (27472).
The spelling of 1214315329 in words is "one billion, two hundred fourteen million, three hundred fifteen thousand, three hundred twenty-nine".
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