Base | Representation |
---|---|
bin | 1011000010110101000110… |
… | …0110000100101000010000 |
3 | 1120222212211101012021011010 |
4 | 2300231101212010220100 |
5 | 3042423324304340340 |
6 | 41454310024050520 |
7 | 2362214562344640 |
oct | 260552146045020 |
9 | 46885741167133 |
10 | 12143241480720 |
11 | 3961a13273429 |
12 | 1441537003a40 |
13 | 6a11449b4bbc |
14 | 2dda43912520 |
15 | 160d184d5b80 |
hex | b0b51984a10 |
12143241480720 has 640 divisors, whose sum is σ = 45123155361792. Its totient is φ = 2642993971200.
The previous prime is 12143241480709. The next prime is 12143241480809. The reversal of 12143241480720 is 2708414234121.
It is a super-3 number, since 3×121432414807203 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 4749017682 + ... + 4749020238.
Almost surely, 212143241480720 is an apocalyptic number.
12143241480720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12143241480720, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22561577680896).
12143241480720 is an abundant number, since it is smaller than the sum of its proper divisors (32979913881072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12143241480720 is a wasteful number, since it uses less digits than its factorization.
12143241480720 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4039 (or 4033 counting only the distinct ones).
The product of its (nonzero) digits is 86016, while the sum is 39.
The spelling of 12143241480720 in words is "twelve trillion, one hundred forty-three billion, two hundred forty-one million, four hundred eighty thousand, seven hundred twenty".
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