12143302141 has 4 divisors (see below), whose sum is σ = 12439480284. Its totient is φ = 11847124000.

The previous prime is 12143302139. The next prime is 12143302151. The reversal of 12143302141 is 14120334121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14120334121 = 10429 ⋅1353949.

It can be written as a sum of positive squares in 2 ways, for example, as 4128576516 + 8014725625 = 64254^2 + 89525^2 .

It is a cyclic number.

It is not a de Polignac number, because 12143302141 - 2¹ = 12143302139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12143302151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148089010 + ... + 148089091.

It is an arithmetic number, because the mean of its divisors is an integer number (3109870071).

Almost surely, 2^12143302141 is an apocalyptic number.

It is an amenable number.

12143302141 is a deficient number, since it is larger than the sum of its proper divisors (296178143).

12143302141 is an equidigital number, since it uses as much as digits as its factorization.

12143302141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 296178142.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 12143302141 its reverse (14120334121), we get a palindrome (26263636262).

The spelling of 12143302141 in words is "twelve billion, one hundred forty-three million, three hundred two thousand, one hundred forty-one".