121433143201 has 4 divisors (see below), whose sum is σ = 121435206912. Its totient is φ = 121431079492.

The previous prime is 121433143163. The next prime is 121433143211. The reversal of 121433143201 is 102341334121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121433143201 - 2¹¹ = 121433141153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121433143211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 940921 + ... + 1062166.

It is an arithmetic number, because the mean of its divisors is an integer number (30358801728).

Almost surely, 2^121433143201 is an apocalyptic number.

It is an amenable number.

121433143201 is a deficient number, since it is larger than the sum of its proper divisors (2063711).

121433143201 is an equidigital number, since it uses as much as digits as its factorization.

121433143201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2063710.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 121433143201 its reverse (102341334121), we get a palindrome (223774477322).

The spelling of 121433143201 in words is "one hundred twenty-one billion, four hundred thirty-three million, one hundred forty-three thousand, two hundred one".