Base | Representation |
---|---|
bin | 111000100010111111… |
… | …1000000111111010010 |
3 | 102121102220001022020201 |
4 | 1301011333000333102 |
5 | 3442143401400224 |
6 | 131441411325414 |
7 | 11526141302233 |
oct | 1610577007722 |
9 | 377386038221 |
10 | 121433231314 |
11 | 4755499100a |
12 | 1b64b8b086a |
13 | b5b30cc835 |
14 | 5c3d82908a |
15 | 325ac11a44 |
hex | 1c45fc0fd2 |
121433231314 has 4 divisors (see below), whose sum is σ = 182149846974. Its totient is φ = 60716615656.
The previous prime is 121433231303. The next prime is 121433231327. The reversal of 121433231314 is 413132334121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 70913027025 + 50520204289 = 266295^2 + 224767^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30358307827 + ... + 30358307830.
Almost surely, 2121433231314 is an apocalyptic number.
121433231314 is a deficient number, since it is larger than the sum of its proper divisors (60716615660).
121433231314 is an equidigital number, since it uses as much as digits as its factorization.
121433231314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60716615659.
The product of its digits is 5184, while the sum is 28.
Adding to 121433231314 its reverse (413132334121), we get a palindrome (534565565435).
The spelling of 121433231314 in words is "one hundred twenty-one billion, four hundred thirty-three million, two hundred thirty-one thousand, three hundred fourteen".
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