121433242213 has 4 divisors (see below), whose sum is σ = 122896293408. Its totient is φ = 119970191020.

The previous prime is 121433242211. The next prime is 121433242219. The reversal of 121433242213 is 312242334121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 312242334121 = 19 ⋅16433807059.

It is a cyclic number.

It is not a de Polignac number, because 121433242213 - 2¹ = 121433242211 is a prime.

It is a super-2 number, since 2×121433242213² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121433242211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 731525473 + ... + 731525638.

It is an arithmetic number, because the mean of its divisors is an integer number (30724073352).

Almost surely, 2^121433242213 is an apocalyptic number.

It is an amenable number.

121433242213 is a deficient number, since it is larger than the sum of its proper divisors (1463051195).

121433242213 is an equidigital number, since it uses as much as digits as its factorization.

121433242213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1463051194.

The product of its digits is 6912, while the sum is 28.

Adding to 121433242213 its reverse (312242334121), we get a palindrome (433675576334).

It can be divided in two parts, 121 and 433242213, that added together give a palindrome (433242334).

The spelling of 121433242213 in words is "one hundred twenty-one billion, four hundred thirty-three million, two hundred forty-two thousand, two hundred thirteen".