12143344444001 has 4 divisors (see below), whose sum is σ = 12289649798832. Its totient is φ = 11997039089172.

The previous prime is 12143344443941. The next prime is 12143344444013. The reversal of 12143344444001 is 10044444334121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12143344444001 - 2²² = 12143340249697 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12143344444031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73152677291 + ... + 73152677456.

It is an arithmetic number, because the mean of its divisors is an integer number (3072412449708).

Almost surely, 2^{12143344444001} is an apocalyptic number.

It is an amenable number.

12143344444001 is a deficient number, since it is larger than the sum of its proper divisors (146305354831).

12143344444001 is an equidigital number, since it uses as much as digits as its factorization.

12143344444001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146305354830.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 12143344444001 its reverse (10044444334121), we get a palindrome (22187788778122).

The spelling of 12143344444001 in words is "twelve trillion, one hundred forty-three billion, three hundred forty-four million, four hundred forty-four thousand, one".