12143344444013 has 2 divisors, whose sum is σ = 12143344444014. Its totient is φ = 12143344444012.

The previous prime is 12143344443941. The next prime is 12143344444031. The reversal of 12143344444013 is 31044444334121.

It is a happy number.

Together with next prime (12143344444031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6569599513129 + 5573744930884 = 2563123^2 + 2360878^2 .

It is a cyclic number.

It is not a de Polignac number, because 12143344444013 - 2¹⁰ = 12143344442989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12143344444043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071672222006 + 6071672222007.

It is an arithmetic number, because the mean of its divisors is an integer number (6071672222007).

Almost surely, 2^{12143344444013} is an apocalyptic number.

It is an amenable number.

12143344444013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12143344444013 is an equidigital number, since it uses as much as digits as its factorization.

12143344444013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 221184, while the sum is 38.

Adding to 12143344444013 its reverse (31044444334121), we get a palindrome (43187788778134).

The spelling of 12143344444013 in words is "twelve trillion, one hundred forty-three billion, three hundred forty-four million, four hundred forty-four thousand, thirteen".