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121434041143 = 991122536873
BaseRepresentation
bin111000100011000001…
…0000110101100110111
3102121102221120110010101
41301012002012230313
53442144103304033
6131441440534531
711526151214242
oct1610602065467
9377387513111
10121434041143
1147555394498
121b650021447
13b5b332431c
145c3d99a259
15325ad2197d
hex1c46086b37

121434041143 has 4 divisors (see below), whose sum is σ = 121556579008. Its totient is φ = 121311503280.

The previous prime is 121434041129. The next prime is 121434041161. The reversal of 121434041143 is 341140434121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121434041143 - 25 = 121434041111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121434041173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61267446 + ... + 61269427.

It is an arithmetic number, because the mean of its divisors is an integer number (30389144752).

Almost surely, 2121434041143 is an apocalyptic number.

121434041143 is a deficient number, since it is larger than the sum of its proper divisors (122537865).

121434041143 is an equidigital number, since it uses as much as digits as its factorization.

121434041143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122537864.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 121434041143 its reverse (341140434121), we get a palindrome (462574475264).

The spelling of 121434041143 in words is "one hundred twenty-one billion, four hundred thirty-four million, forty-one thousand, one hundred forty-three".

Divisors: 1 991 122536873 121434041143