12144002013043 has 4 divisors (see below), whose sum is σ = 12144052747728. Its totient is φ = 12143951278360.

The previous prime is 12144002013037. The next prime is 12144002013061. The reversal of 12144002013043 is 34031020044121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12144002013043 - 2⁹ = 12144002012531 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12144002012999 and 12144002013017.

It is not an unprimeable number, because it can be changed into a prime (12144002013083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25006588 + ... + 25487593.

It is an arithmetic number, because the mean of its divisors is an integer number (3036013186932).

Almost surely, 2^{12144002013043} is an apocalyptic number.

12144002013043 is a deficient number, since it is larger than the sum of its proper divisors (50734685).

12144002013043 is an equidigital number, since it uses as much as digits as its factorization.

12144002013043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50734684.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12144002013043 its reverse (34031020044121), we get a palindrome (46175022057164).

The spelling of 12144002013043 in words is "twelve trillion, one hundred forty-four billion, two million, thirteen thousand, forty-three".