Base | Representation |
---|---|
bin | 1011000010111000010100… |
… | …0110001010101010001101 |
3 | 1120222222001121001121202001 |
4 | 2300232011012022222031 |
5 | 3042432112004011140 |
6 | 41454531451432301 |
7 | 2362245153561004 |
oct | 260560506125215 |
9 | 46888047047661 |
10 | 12144105532045 |
11 | 3962316a81a33 |
12 | 1441738455691 |
13 | 6a1251a02a86 |
14 | 2ddac6591c3b |
15 | 160d692b0e9a |
hex | b0b8518aa8d |
12144105532045 has 16 divisors (see below), whose sum is σ = 15343402536000. Its totient is φ = 9201865811328.
The previous prime is 12144105531913. The next prime is 12144105532051. The reversal of 12144105532045 is 54023550144121.
It is not a de Polignac number, because 12144105532045 - 225 = 12144071977613 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12144105531995 and 12144105532013.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14077935 + ... + 14915644.
It is an arithmetic number, because the mean of its divisors is an integer number (958962658500).
Almost surely, 212144105532045 is an apocalyptic number.
It is an amenable number.
12144105532045 is a deficient number, since it is larger than the sum of its proper divisors (3199297003955).
12144105532045 is a wasteful number, since it uses less digits than its factorization.
12144105532045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28998012.
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 12144105532045 its reverse (54023550144121), we get a palindrome (66167655676166).
The spelling of 12144105532045 in words is "twelve trillion, one hundred forty-four billion, one hundred five million, five hundred thirty-two thousand, forty-five".
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