Base | Representation |
---|---|
bin | 10001101011000000101… |
… | …010010101110010101111 |
3 | 11022002121112111120022111 |
4 | 101223000222111302233 |
5 | 124344104223233010 |
6 | 2325521011224451 |
7 | 153511201023223 |
oct | 21530052256257 |
9 | 4262545446274 |
10 | 1214413102255 |
11 | 42903659a151 |
12 | 1774405a8127 |
13 | 8a698674a92 |
14 | 42ac6816783 |
15 | 218ca21e58a |
hex | 11ac0a95caf |
1214413102255 has 4 divisors (see below), whose sum is σ = 1457295722712. Its totient is φ = 971530481800.
The previous prime is 1214413102247. The next prime is 1214413102291. The reversal of 1214413102255 is 5522013144121.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1214413102255 - 23 = 1214413102247 is a prime.
It is a super-2 number, since 2×12144131022552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121441310221 + ... + 121441310230.
It is an arithmetic number, because the mean of its divisors is an integer number (364323930678).
Almost surely, 21214413102255 is an apocalyptic number.
1214413102255 is a deficient number, since it is larger than the sum of its proper divisors (242882620457).
1214413102255 is an equidigital number, since it uses as much as digits as its factorization.
1214413102255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 242882620456.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 1214413102255 its reverse (5522013144121), we get a palindrome (6736426246376).
The spelling of 1214413102255 in words is "one trillion, two hundred fourteen billion, four hundred thirteen million, one hundred two thousand, two hundred fifty-five".
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