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1214444302051 = 2232535439767
BaseRepresentation
bin10001101011000010100…
…001010110111011100011
311022002200201012200101111
4101223002201112323203
5124344140220131201
62325524044044151
7153512030146561
oct21530241267343
94262621180344
101214444302051
1142905216a002
1217744ab33657
138a6a1c79bb6
1442acaa18a31
15218ccd33b51
hex11ac2856ee3

1214444302051 has 4 divisors (see below), whose sum is σ = 1214449965072. Its totient is φ = 1214438639032.

The previous prime is 1214444301997. The next prime is 1214444302061. The reversal of 1214444302051 is 1502034444121.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1214444302051 - 223 = 1214435913443 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1214444302061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2496631 + ... + 2943136.

It is an arithmetic number, because the mean of its divisors is an integer number (303612491268).

Almost surely, 21214444302051 is an apocalyptic number.

1214444302051 is a deficient number, since it is larger than the sum of its proper divisors (5663021).

1214444302051 is an equidigital number, since it uses as much as digits as its factorization.

1214444302051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5663020.

The product of its (nonzero) digits is 15360, while the sum is 31.

Adding to 1214444302051 its reverse (1502034444121), we get a palindrome (2716478746172).

The spelling of 1214444302051 in words is "one trillion, two hundred fourteen billion, four hundred forty-four million, three hundred two thousand, fifty-one".

Divisors: 1 223253 5439767 1214444302051