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121451140564331 = 415729216054983
BaseRepresentation
bin11011100111010110001100…
…000101110100010101101011
3120221000121121210202200011112
4123213112030011310111223
5111404323413441024311
61110145514515220535
734403361324361334
oct3347261405642553
9527017553680145
10121451140564331
11357751596953a6
12117560652a774b
13529ca411878a6
1421dc3a366728b
15e0935235528b
hex6e758c17456b

121451140564331 has 4 divisors (see below), whose sum is σ = 121480356623472. Its totient is φ = 121421924505192.

The previous prime is 121451140564307. The next prime is 121451140564339. The reversal of 121451140564331 is 133465041154121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121451140564331 - 242 = 117053094053227 is a prime.

It is a super-2 number, since 2×1214511405643312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121451140564339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14608023335 + ... + 14608031648.

It is an arithmetic number, because the mean of its divisors is an integer number (30370089155868).

Almost surely, 2121451140564331 is an apocalyptic number.

121451140564331 is a deficient number, since it is larger than the sum of its proper divisors (29216059141).

121451140564331 is an equidigital number, since it uses as much as digits as its factorization.

121451140564331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29216059140.

The product of its (nonzero) digits is 172800, while the sum is 41.

The spelling of 121451140564331 in words is "one hundred twenty-one trillion, four hundred fifty-one billion, one hundred forty million, five hundred sixty-four thousand, three hundred thirty-one".

Divisors: 1 4157 29216054983 121451140564331