Base | Representation |
---|---|
bin | 11110010110001011000000… |
… | …010111100011000001001001 |
3 | 122111120010121012020220100212 |
4 | 132112023000113203001021 |
5 | 114443142401013412441 |
6 | 1151504554331210505 |
7 | 40053350065434605 |
oct | 3626130027430111 |
9 | 574503535226325 |
10 | 133465041154121 |
11 | 3958722a33a036 |
12 | 12b765042a6a35 |
13 | 59619126bb121 |
14 | 24d5a57442505 |
15 | 1066aea7bdeeb |
hex | 7962c05e3049 |
133465041154121 has 2 divisors, whose sum is σ = 133465041154122. Its totient is φ = 133465041154120.
The previous prime is 133465041154103. The next prime is 133465041154163. The reversal of 133465041154121 is 121451140564331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 89689139089225 + 43775902064896 = 9470435^2 + 6616336^2 .
It is a cyclic number.
It is not a de Polignac number, because 133465041154121 - 26 = 133465041154057 is a prime.
It is not a weakly prime, because it can be changed into another prime (133465041154321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66732520577060 + 66732520577061.
It is an arithmetic number, because the mean of its divisors is an integer number (66732520577061).
Almost surely, 2133465041154121 is an apocalyptic number.
It is an amenable number.
133465041154121 is a deficient number, since it is larger than the sum of its proper divisors (1).
133465041154121 is an equidigital number, since it uses as much as digits as its factorization.
133465041154121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 41.
The spelling of 133465041154121 in words is "one hundred thirty-three trillion, four hundred sixty-five billion, forty-one million, one hundred fifty-four thousand, one hundred twenty-one".
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