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1214520350055 = 35223936162583
BaseRepresentation
bin10001101011000111000…
…011011101010101100111
311022002220000022022122020
4101223013003131111213
5124344314202200210
62325535402034223
7153513642433065
oct21530703352547
94262800268566
101214520350055
11429091090aa1
121774704a8973
138a6b495550c
1442ad6b73035
15218d4856770
hex11ac70dd567

1214520350055 has 16 divisors (see below), whose sum is σ = 1944100515840. Its totient is φ = 647454868128.

The previous prime is 1214520350023. The next prime is 1214520350081. The reversal of 1214520350055 is 5500530254121.

It is not a de Polignac number, because 1214520350055 - 25 = 1214520350023 is a prime.

It is a super-3 number, since 3×12145203500553 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1214520349998 and 1214520350025.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18047707 + ... + 18114876.

It is an arithmetic number, because the mean of its divisors is an integer number (121506282240).

Almost surely, 21214520350055 is an apocalyptic number.

1214520350055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1214520350055 is a deficient number, since it is larger than the sum of its proper divisors (729580165785).

1214520350055 is a wasteful number, since it uses less digits than its factorization.

1214520350055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36164830.

The product of its (nonzero) digits is 30000, while the sum is 33.

The spelling of 1214520350055 in words is "one trillion, two hundred fourteen billion, five hundred twenty million, three hundred fifty thousand, fifty-five".

Divisors: 1 3 5 15 2239 6717 11195 33585 36162583 108487749 180812915 542438745 80968023337 242904070011 404840116685 1214520350055