1214522040433 has 8 divisors (see below), whose sum is σ = 1308053486376. Its totient is φ = 1121005833600.

The previous prime is 1214522040421. The next prime is 1214522040437. The reversal of 1214522040433 is 3340402254121.

It can be written as a sum of positive squares in 4 ways, for example, as 2391503409 + 1212130537024 = 48903^2 + 1100968^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1214522040433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1214522040395 and 1214522040404.

It is not an unprimeable number, because it can be changed into a prime (1214522040437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3643978 + ... + 3963283.

It is an arithmetic number, because the mean of its divisors is an integer number (163506685797).

Almost surely, 2^{1214522040433} is an apocalyptic number.

1214522040433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1214522040433 is a deficient number, since it is larger than the sum of its proper divisors (93531445943).

1214522040433 is a wasteful number, since it uses less digits than its factorization.

1214522040433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7619555.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 1214522040433 its reverse (3340402254121), we get a palindrome (4554924294554).

The spelling of 1214522040433 in words is "one trillion, two hundred fourteen billion, five hundred twenty-two million, forty thousand, four hundred thirty-three".