Search a number
-
+
1214522040437 is a prime number
BaseRepresentation
bin10001101011000111001…
…001111010000001110101
311022002220010111012101222
4101223013021322001311
5124344320120243222
62325535502200125
7153513663003236
oct21530711720165
94262803435358
101214522040437
11429092036002
12177470b83045
138a6b50c7a44
1442ad709308d
15218d4a8c542
hex11ac727a075

1214522040437 has 2 divisors, whose sum is σ = 1214522040438. Its totient is φ = 1214522040436.

The previous prime is 1214522040421. The next prime is 1214522040443. The reversal of 1214522040437 is 7340402254121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1132115152081 + 82406888356 = 1064009^2 + 287066^2 .

It is a cyclic number.

It is not a de Polignac number, because 1214522040437 - 24 = 1214522040421 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1214522040397 and 1214522040406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1214522040497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607261020218 + 607261020219.

It is an arithmetic number, because the mean of its divisors is an integer number (607261020219).

Almost surely, 21214522040437 is an apocalyptic number.

It is an amenable number.

1214522040437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214522040437 is an equidigital number, since it uses as much as digits as its factorization.

1214522040437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 53760, while the sum is 35.

Adding to 1214522040437 its reverse (7340402254121), we get a palindrome (8554924294558).

The spelling of 1214522040437 in words is "one trillion, two hundred fourteen billion, five hundred twenty-two million, forty thousand, four hundred thirty-seven".