1214553140343 has 6 divisors (see below), whose sum is σ = 1754354536064. Its totient is φ = 809702093556.

The previous prime is 1214553140309. The next prime is 1214553140369. The reversal of 1214553140343 is 3430413554121.

1214553140343 is a `hidden beast` number, since 1 + 2 + 1 + 45 + 531 + 40 + 3 + 43 = 666.

It is not a de Polignac number, because 1214553140343 - 2²⁴ = 1214536363127 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1214553140298 and 1214553140307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214553140743) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 67475174455 + ... + 67475174472.

Almost surely, 2^{1214553140343} is an apocalyptic number.

1214553140343 is a deficient number, since it is larger than the sum of its proper divisors (539801395721).

1214553140343 is a wasteful number, since it uses less digits than its factorization.

1214553140343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134950348933 (or 134950348930 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 36.

Adding to 1214553140343 its reverse (3430413554121), we get a palindrome (4644966694464).

It can be divided in two parts, 1214553 and 140343, that added together give a square (1354896 = 1164²).

The spelling of 1214553140343 in words is "one trillion, two hundred fourteen billion, five hundred fifty-three million, one hundred forty thousand, three hundred forty-three".